Topic 5.15 · teacher page · Higher Level

Running slope fields

A field is every solution at once, which is exactly what a printed curve cannot show.

The one thing to do with the animation

Let them tap, and watch the curves refuse to cross.

Drop three or four curves on the first field and the family appears. Then ask whether two could ever meet. They crowd together and never touch, because each point has exactly one gradient.

The logistic field is the one to finish on: everything levels off at y = 1, and the constant solutions along y = 0 and y = 1 are visible as rows of flat dashes.

The assessed skill is reading, not drawing

Students are asked to use and interpret slope fields. Sketching a solution on a printed field, and describing long-term behaviour, is what comes up.

So spend the time on following dashes accurately and naming what a curve tends towards, not on generating fields by hand.

The answers

dy/dx = x − yFlat dashes along y = x. Solutions bend towards the line y = x − 1.
dy/dx = y(1 − y)Constant solutions at y = 0 and y = 1. Everything between rises to 1; anything above falls to it.
dy/dx = −x/yCircles, since x² + y² is constant.
1. Along y = xA, horizontal, since x − y = 0 there.
2. Why curves cannot crossB. One gradient per point.
3. Starting at y = 0.3B, levels off at y = 1.

Where the marks go

1 markStarting the sketch at the given point. A correct shape in the wrong place earns nothing.

1 markStaying tangent to the dashes along the whole curve.

1 markDescribing long-term behaviour: which line, and from which side.

What each wrong answer tells you

They giveWhat it means
Gradient 1 along y = x (Q1)Confused the gradient of the LINE with the gradient the field prescribes. Very common, and worth a board sketch.
"Curves are parallel" (Q2)Plausible from a tidy field, and wrong. Drop two curves and watch them diverge.
"Grows without limit" (Q3)Did not look at the gradient above y = 1, where it turns negative.
A sketch crossing y = 1The clearest possible signal that the field was not being followed. Constant solutions are walls.

Other things they will say

"Do I have to solve it?" No, and that is the point. The field gives the shape with no solving at all, which is why it exists for equations that cannot be solved.

"Why are some dashes nearly vertical?" Because the gradient is large there. On a printed field they are drawn the same length regardless, which is why they look like a texture rather than a scale.

"What if my curve runs off the page?" Fine. Draw it to the edge. Running off is itself a description of the behaviour.

A possible order

 What is happening
1Show a field with no equation. What is it telling us? Let them work out that each dash is a gradient.
2Tap to drop curves. Build the family and the no-crossing rule.
3Sketching by hand on a printed field, starting from a marked point.
4The logistic field and long-term behaviour in words.
5Questions 1 to 3, and a past-paper style sketch.
6Link forward: Euler is this, done numerically.

Two things not to say

Do not have them generate a field by hand beyond a handful of points. It is slow, it is not what is assessed, and it eats the lesson.

Do not accept a sketch that crosses a constant solution. It is the quickest way to see that a student is drawing a shape they expect rather than following the field.

Questions to set

Three tiers, ramping the way practice should: the method on its own, then the method inside something real, then a challenge. Set the tier the class in front of you needs rather than one undifferentiated sheet. Answers are given so these can go straight onto a board.

1Fluency

The method on its own, with friendly numbers. Set these first and move on quickly once they are secure.

  1. Read a slopeFor dy/dx = x + y, state the gradient of the solution through (1, 2).
    3
  2. Find the flat lineFor the same equation, find where the slope field is horizontal.
    x + y = 0, so along the line y = −x.

2In context

The same skill inside a real situation, where the first job is working out what is being asked.

  1. Sketch a curveStarting at (0, 1), describe the solution curve of dy/dx = x + y.
    It leaves with gradient 1 and steepens as both x and y grow, so it curves upwards away from the origin, faster and faster.
  2. One field, many curvesExplain why a slope field shows infinitely many solution curves.
    The equation fixes only the gradient at each point, not a starting value. Each initial condition picks out one curve, and they fill the plane without crossing.

3Challenge

Reasoning, working backwards, or spotting an error. These are where the top grades are decided.

  1. Equilibrium from the fieldFor dy/dx = y(1 − y), find where the field is horizontal and describe the behaviour near each.
    At y = 0 and y = 1. Just above 0 the slope is positive and just below 1 it is still positive, so solutions climb from 0 towards 1: y = 1 is stable and y = 0 is unstable.
  2. What a field cannot tell youState what a slope field shows and what it does not.
    It shows the direction of every solution everywhere, so the shape and the long-run behaviour. It gives no numerical value for any particular solution, which is what Euler's method or an exact solution is for.

Practicalities

Works on a phone. Nothing is loaded from any other site, so it runs behind a school firewall, and nothing a student does is saved or sent anywhere.