Topic 5.3 · AA and AI, SL and HL

Multiply by the power, then knock one off it

The rule in two moves, applied term by term, and the one kind of power your course does not ask you to touch.

In 5.1 the gradient was a limit you estimated from a table. Nobody wants to build a table every time, so there is a rule. Press play and watch it happen to one term.

3x4 start One term. The power is 4 and the coefficient is 3.
3x4 → 12x4 Move 1. Multiply the front by the power: 4 × 3 = 12.
12x4 → 12x3 Move 2. Knock one off the power: 4 − 1 = 3.
If f(x) = axn then f′(x) = anxn−1
Two moves, always in that order.

Every term, one at a time

A polynomial is just several of those, and you do each one separately. Press play and watch each term get the same treatment.

f(x) = 3x4 − 5x2 + 7x − 2

3x4→ 12x3 4 × 3 = 12, and the power drops to 3.
−5x2→ −10x 2 × −5 = −10, and x1 is just x.
7x→ 7 7x is 7x1, so 1 × 7 = 7 and x0 = 1. A straight line has a constant gradient.
−2→ 0 A constant has no slope. Shifting a graph up or down never changes its gradient.
f′(x) = 12x3 − 10x + 7
Signs travel with their term.

Does the rule actually give the gradient?

Fair question, since 5.1 said a gradient was a limit. So let us check. On the left is the rule. On the right is a real chord across a tiny gap, worked out the 5.1 way. Move x and watch them agree.

g(x) = 2x³ + x² − 4x + 9   so   g′(x) = 6x² + 2x − 4

x = 1.00
4.000from the rule
4.000from a tiny chord

The chord uses a gap of 0.0001 either side. They agree to three decimal places everywhere, which is the point.

Negative powers are in. Roots are not.

On Applications and Interpretation the power n is a whole number. It can be negative, so 1⁄x² is fair game. It is never a fraction, so you are not asked to differentiate √x on this course.

If you are using a textbook or a video made for Analysis and Approaches you will meet √x = x1/2 differentiated as if it were routine. For AI that is extra work you cannot be examined on.

Worked example: a negative power

Differentiate h(x) = 4x².

h(x)= 4x−2 rewrite it as a power first, always h′(x)= −2 × 4x−2−1 = −8x−3 the rule, unchanged = −8x³ back to a fraction if the question used one

Check it at x = 2: −8 ÷ 8 = −1. Negative, which fits, because 4⁄x² is falling at x = 2.

Knocking one off a negative power makes it more negative. −2 − 1 = −3, not −1. This is the single most common slip on this sub-topic, and it is a subtraction error rather than a calculus one.

Your turn

1. For f(x) = 3x4 − 5x² + 7x − 2, find f′(1).

2. Differentiate 4x².

3. Which of these are you not expected to differentiate on Applications and Interpretation?

Where the marks go

Rewrite fractions as powers before you differentiate. Trying to differentiate 4⁄x² while it still looks like a fraction is where most wrong answers begin.

Do not lose the constant term by forgetting it exists. It differentiates to zero, which is a thing you did, not a thing you skipped.

If the question says "hence" it wants you to use the derivative you just found. A fresh calculator answer that ignores your own working can cost the method marks even when the number is right.

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