Topic 5.9 · AI Higher Level

The radius grows steadily. The area does not.

Three rules for differentiating combinations, the standard derivatives, and what to do when two rates are linked.

Higher Level

Drop a stone into a klong. The ripple's radius grows at a steady half a metre per second. Watch what the area does.

t = 2.0 s
1.0radius, m
0.50dr/dt, m per s
3.14dA/dt, m² per s

The radius rate never changes. The area rate keeps climbing, because it depends on the radius.

Related rates, which is the chain rule wearing a coat

A= πr², so dAdr = 2πr dAdt= dAdr × drdt the chain rule, with the dr cancelling by eye = 2π(3) × 0.5 = 3π ≈ 9.42 m² per s when the radius is 3 m

Write the chain before you substitute. Deciding which derivative you want, which one you were given, and what links them is the whole method. Numbers go in last, and a question that asks "at the instant when r = 3" is telling you to substitute at the end, not the start.

The three rules

chain→ f′(g)·g′ A function inside another. Differentiate the outside, leave the inside alone, then multiply by the inside's derivative.
product→ u′v + uv′ Two functions multiplied. Each one takes a turn at being differentiated.
quotient→ u′v − uv′v² A fraction. The order matters here: top derivative first, and the whole thing over the bottom squared.
Pick the rule from the shape, not the letters.

One of each

y = (3x + 1)⁵→ 5(3x + 1)⁴ × 3 = 15(3x + 1)⁴ chain. At x = 0 that is 15 y = x²e𝕩→ 2xe𝕩 + x²e𝕩 = e𝕩(2x + x²) product. At x = 1 that is 3e ≈ 8.155 y = xx + 1→ 1(x + 1) − x(1)(x + 1)² = 1(x + 1)² quotient. At x = 1 that is ¼

The standard derivatives

f(x)sin xcos xtan xexln xxn
f′(x)cos x−sin x1cos²xex1xnxn−1

The scope just widened. At Standard Level the index n had to be a whole number, so √x was out. At Higher Level n can be any fraction, so √x = x½ differentiates to 1⁄2√x, which is ¼ at x = 4. If you learned at SL that roots were not your problem, they are now.

Radians, always. The derivative of sin x is cos x only when x is in radians. A calculator left in degrees will quietly give wrong gradients all the way through a question.

Your turn

1. Differentiate y = (3x + 1)⁵ and find the gradient at x = 0.

2. Which rule does y = x²e𝕩 need?

3. The ripple's radius grows at 0.5 m per second. Find dAdt when r = 3, to 2 decimal places.

Where the marks go

Naming the rule correctly is usually implicit, but applying the quotient rule with the terms the wrong way round is not recoverable: u′v comes first.

On a related rates question, writing the chain of derivatives before any numbers is normally an explicit mark, and it is what makes the rest possible.

Leaving a chain rule half done, differentiating the outside and forgetting to multiply by the inside's derivative, is the single commonest error in this sub-topic. The missing factor is usually a small number like 3, so the answer still looks plausible.

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